Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101010110010100100111011 |
3 | 122011212122101111201101120102 |
4 | 131302132213222302210323 |
5 | 114133000441303122141 |
6 | 1142350101330150015 |
7 | 36411214313412656 |
oct | 3562364752624473 |
9 | 564778344641512 |
10 | 131012200442171 |
11 | 38820a64739984 |
12 | 1283b060a2230b |
13 | 5814522395b79 |
14 | 244d04aabc89d |
15 | 1022ddbe7599b |
hex | 7727a7ab293b |
131012200442171 has 2 divisors, whose sum is σ = 131012200442172. Its totient is φ = 131012200442170.
The previous prime is 131012200442161. The next prime is 131012200442173. The reversal of 131012200442171 is 171244002210131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131012200442171 - 210 = 131012200441147 is a prime.
Together with 131012200442173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131012200442173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100221085 + 65506100221086.
It is an arithmetic number, because the mean of its divisors is an integer number (65506100221086).
Almost surely, 2131012200442171 is an apocalyptic number.
131012200442171 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012200442171 is an equidigital number, since it uses as much as digits as its factorization.
131012200442171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
The spelling of 131012200442171 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, four hundred forty-two thousand, one hundred seventy-one".
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