13101220113221 has 4 divisors (see below), whose sum is σ = 13420762067244. Its totient is φ = 12781678159200.

The previous prime is 13101220113211. The next prime is 13101220113227. The reversal of 13101220113221 is 12231102210131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4946683084996 + 8154537028225 = 2224114^2 + 2855615^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101220113221 - 2³⁸ = 12826342206277 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101220113193 and 13101220113202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101220113227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159770976950 + ... + 159770977031.

It is an arithmetic number, because the mean of its divisors is an integer number (3355190516811).

Almost surely, 2^{13101220113221} is an apocalyptic number.

It is an amenable number.

13101220113221 is a deficient number, since it is larger than the sum of its proper divisors (319541954023).

13101220113221 is an equidigital number, since it uses as much as digits as its factorization.

13101220113221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 319541954022.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13101220113221 its reverse (12231102210131), we get a palindrome (25332322323352).

The spelling of 13101220113221 in words is "thirteen trillion, one hundred one billion, two hundred twenty million, one hundred thirteen thousand, two hundred twenty-one".