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13101222012311 is a prime number
BaseRepresentation
bin1011111010100101110110…
…1011110010010110010111
31201101110112200120112021102
42332221131223302112113
53204122300313343221
643510341315340315
72521350331455116
oct276513553622627
951343480515242
1013101222012311
1141a1219306824
1215771308b169b
137405946c8664
143341614a5c7d
1517abd5d0930b
hexbea5daf2597

13101222012311 has 2 divisors, whose sum is σ = 13101222012312. Its totient is φ = 13101222012310.

The previous prime is 13101222012301. The next prime is 13101222012313. The reversal of 13101222012311 is 11321022210131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13101222012311 is a prime.

Together with 13101222012313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101222012313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550611006155 + 6550611006156.

It is an arithmetic number, because the mean of its divisors is an integer number (6550611006156).

Almost surely, 213101222012311 is an apocalyptic number.

13101222012311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101222012311 is an equidigital number, since it uses as much as digits as its factorization.

13101222012311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13101222012311 its reverse (11321022210131), we get a palindrome (24422244222442).

The spelling of 13101222012311 in words is "thirteen trillion, one hundred one billion, two hundred twenty-two million, twelve thousand, three hundred eleven".