Base | Representation |
---|---|
bin | 111101000000011110… |
… | …0011000011110110101 |
3 | 110112011110211000022001 |
4 | 1322000330120132311 |
5 | 4121303124101240 |
6 | 140104120535301 |
7 | 12315415304662 |
oct | 1720074303665 |
9 | 415143730261 |
10 | 131012331445 |
11 | 50620055796 |
12 | 21483921531 |
13 | c47b83b818 |
14 | 64abb06a69 |
15 | 361bb7d89a |
hex | 1e80f187b5 |
131012331445 has 4 divisors (see below), whose sum is σ = 157214797740. Its totient is φ = 104809865152.
The previous prime is 131012331389. The next prime is 131012331481. The reversal of 131012331445 is 544133210131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 66163671729 + 64848659716 = 257223^2 + 254654^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012331445 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13101233140 + ... + 13101233149.
It is an arithmetic number, because the mean of its divisors is an integer number (39303699435).
Almost surely, 2131012331445 is an apocalyptic number.
It is an amenable number.
131012331445 is a deficient number, since it is larger than the sum of its proper divisors (26202466295).
131012331445 is an equidigital number, since it uses as much as digits as its factorization.
131012331445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26202466294.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 131012331445 its reverse (544133210131), we get a palindrome (675145541576).
The spelling of 131012331445 in words is "one hundred thirty-one billion, twelve million, three hundred thirty-one thousand, four hundred forty-five".
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