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1310130121333 = 11119102738303
BaseRepresentation
bin10011000100001001110…
…101110010101001110101
311122020200012221221021011
4103010021311302221311
5132431121302340313
62441510535152221
7163440150200665
oct23041165625165
94566605857234
101310130121333
114656943312a0
12191ab3b15671
1396710a43687
14475a6b001a5
152412d43793d
hex13109d72a75

1310130121333 has 4 divisors (see below), whose sum is σ = 1429232859648. Its totient is φ = 1191027383020.

The previous prime is 1310130121327. The next prime is 1310130121361. The reversal of 1310130121333 is 3331210310131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310130121333 - 29 = 1310130120821 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310130121033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59551369141 + ... + 59551369162.

It is an arithmetic number, because the mean of its divisors is an integer number (357308214912).

Almost surely, 21310130121333 is an apocalyptic number.

It is an amenable number.

1310130121333 is a deficient number, since it is larger than the sum of its proper divisors (119102738315).

1310130121333 is a wasteful number, since it uses less digits than its factorization.

1310130121333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119102738314.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1310130121333 its reverse (3331210310131), we get a palindrome (4641340431464).

The spelling of 1310130121333 in words is "one trillion, three hundred ten billion, one hundred thirty million, one hundred twenty-one thousand, three hundred thirty-three".

Divisors: 1 11 119102738303 1310130121333