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131013111103 = 718716158729
BaseRepresentation
bin111101000000011111…
…1010110110100111111
3110112011112021121210021
41322000333112310333
54121303324023403
6140104145353011
712315425033020
oct1720077266477
9415145247707
10131013111103
1150620538536
1221484038767
13c47ba52664
1464abc6ac47
15361bc848bd
hex1e80fd6d3f

131013111103 has 4 divisors (see below), whose sum is σ = 149729269840. Its totient is φ = 112296952368.

The previous prime is 131013111101. The next prime is 131013111109. The reversal of 131013111103 is 301111310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131013111103 - 21 = 131013111101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131013111101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9358079358 + ... + 9358079371.

It is an arithmetic number, because the mean of its divisors is an integer number (37432317460).

Almost surely, 2131013111103 is an apocalyptic number.

131013111103 is a deficient number, since it is larger than the sum of its proper divisors (18716158737).

131013111103 is an equidigital number, since it uses as much as digits as its factorization.

131013111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18716158736.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 131013111103 its reverse (301111310131), we get a palindrome (432124421234).

The spelling of 131013111103 in words is "one hundred thirty-one billion, thirteen million, one hundred eleven thousand, one hundred three".

Divisors: 1 7 18716158729 131013111103