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13101312231989 is a prime number
BaseRepresentation
bin1011111010100110001100…
…0011111100101000110101
31201101110202222100011101222
42332221203003330220311
53204122441412410424
643510354301200125
72521352505354212
oct276514303745065
951343688304358
1013101312231989
1141a1265228143
121577156b60045
137405aa2c6597
1433416d46cb09
1517abddbcae5e
hexbea630fca35

13101312231989 has 2 divisors, whose sum is σ = 13101312231990. Its totient is φ = 13101312231988.

The previous prime is 13101312231947. The next prime is 13101312232033. The reversal of 13101312231989 is 98913221310131.

It is an a-pointer prime, because the next prime (13101312232033) can be obtained adding 13101312231989 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10005676080625 + 3095636151364 = 3163175^2 + 1759442^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13101312231989 is a prime.

It is a super-2 number, since 2×131013122319892 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101312231929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550656115994 + 6550656115995.

It is an arithmetic number, because the mean of its divisors is an integer number (6550656115995).

Almost surely, 213101312231989 is an apocalyptic number.

It is an amenable number.

13101312231989 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101312231989 is an equidigital number, since it uses as much as digits as its factorization.

13101312231989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 44.

The spelling of 13101312231989 in words is "thirteen trillion, one hundred one billion, three hundred twelve million, two hundred thirty-one thousand, nine hundred eighty-nine".