Base | Representation |
---|---|
bin | 10011000100001001111… |
… | …001111111111011011111 |
3 | 11122020200022000222020022 |
4 | 103010021321333323133 |
5 | 132431122043134122 |
6 | 2441511014542355 |
7 | 163440162443414 |
oct | 23041171777337 |
9 | 4566608028208 |
10 | 1310131224287 |
11 | 465694a14a26 |
12 | 191ab43679bb |
13 | 9671103b702 |
14 | 475a6d0a10b |
15 | 2412d5a4642 |
hex | 13109e7fedf |
1310131224287 has 2 divisors, whose sum is σ = 1310131224288. Its totient is φ = 1310131224286.
The previous prime is 1310131224277. The next prime is 1310131224293. The reversal of 1310131224287 is 7824221310131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310131224287 - 24 = 1310131224271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310131224277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065612143 + 655065612144.
It is an arithmetic number, because the mean of its divisors is an integer number (655065612144).
Almost surely, 21310131224287 is an apocalyptic number.
1310131224287 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310131224287 is an equidigital number, since it uses as much as digits as its factorization.
1310131224287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 1310131224287 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, two hundred twenty-four thousand, two hundred eighty-seven".
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