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131013330122020 = 22544831461223847
BaseRepresentation
bin11101110010011111101011…
…000000001011010100100100
3122011212202022020102001222211
4131302133223000023110210
5114133010300002401040
61142350405403133204
736411254311502143
oct3562375300132444
9564782266361884
10131013330122020
1138821494386095
121283b317214204
135814672438b98
14244d116b4575a
151022e562208ea
hex7727eb00b524

131013330122020 has 24 divisors (see below), whose sum is σ = 275189364846144. Its totient is φ = 52393642222176.

The previous prime is 131013330122011. The next prime is 131013330122023. The reversal of 131013330122020 is 20221033310131.

It is a super-2 number, since 2×1310133301220202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131013330121982 and 131013330122000.

It is not an unprimeable number, because it can be changed into a prime (131013330122023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 730522264 + ... + 730701583.

It is an arithmetic number, because the mean of its divisors is an integer number (11466223535256).

Almost surely, 2131013330122020 is an apocalyptic number.

131013330122020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131013330122020 is an abundant number, since it is smaller than the sum of its proper divisors (144176034724124).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131013330122020 is a wasteful number, since it uses less digits than its factorization.

131013330122020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1461228339 (or 1461228337 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 131013330122020 its reverse (20221033310131), we get a palindrome (151234363432151).

The spelling of 131013330122020 in words is "one hundred thirty-one trillion, thirteen billion, three hundred thirty million, one hundred twenty-two thousand, twenty".

Divisors: 1 2 4 5 10 20 4483 8966 17932 22415 44830 89660 1461223847 2922447694 5844895388 7306119235 14612238470 29224476940 6550666506101 13101333012202 26202666024404 32753332530505 65506665061010 131013330122020