13101341011033 has 4 divisors (see below), whose sum is σ = 14292372012048. Its totient is φ = 11910310010020.

The previous prime is 13101341011009. The next prime is 13101341011051. The reversal of 13101341011033 is 33011014310131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101341011033 - 2⁵ = 13101341011001 is a prime.

It is a super-4 number, since 4×13101341011033⁴ (a number of 54 digits) contains 4444 as substring.

It is a Smith number, since the sum of its digits (22) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101341010995 and 13101341011013.

It is not an unprimeable number, because it can be changed into a prime (13101341011433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595515500491 + ... + 595515500512.

It is an arithmetic number, because the mean of its divisors is an integer number (3573093003012).

Almost surely, 2^{13101341011033} is an apocalyptic number.

It is an amenable number.

13101341011033 is a deficient number, since it is larger than the sum of its proper divisors (1191031001015).

13101341011033 is a wasteful number, since it uses less digits than its factorization.

13101341011033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191031001014.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13101341011033 its reverse (33011014310131), we get a palindrome (46112355321164).

The spelling of 13101341011033 in words is "thirteen trillion, one hundred one billion, three hundred forty-one million, eleven thousand, thirty-three".