Base | Representation |
---|---|
bin | 111101000000100001… |
… | …0110111010001100001 |
3 | 110112011121000022212112 |
4 | 1322001002313101201 |
5 | 4121304042433213 |
6 | 140104221205105 |
7 | 12315435612206 |
oct | 1720102672141 |
9 | 415147008775 |
10 | 131014030433 |
11 | 50621006210 |
12 | 21484400795 |
13 | c47bcb4c40 |
14 | 64ac029cad |
15 | 361bdb6ea8 |
hex | 1e810b7461 |
131014030433 has 16 divisors (see below), whose sum is σ = 156527380800. Its totient is φ = 108078415680.
The previous prime is 131014030409. The next prime is 131014030501. The reversal of 131014030433 is 334030410131.
It is a cyclic number.
It is not a de Polignac number, because 131014030433 - 26 = 131014030369 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131014030399 and 131014030408.
It is not an unprimeable number, because it can be changed into a prime (131014035433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7755818 + ... + 7772691.
It is an arithmetic number, because the mean of its divisors is an integer number (9782961300).
Almost surely, 2131014030433 is an apocalyptic number.
131014030433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
131014030433 is a deficient number, since it is larger than the sum of its proper divisors (25513350367).
131014030433 is a wasteful number, since it uses less digits than its factorization.
131014030433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15528592.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131014030433 its reverse (334030410131), we get a palindrome (465044440564).
The spelling of 131014030433 in words is "one hundred thirty-one billion, fourteen million, thirty thousand, four hundred thirty-three".
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