| Base | Representation |
|---|---|
| bin | 11101110010100101111001… |
| … | …111000000011000000100000 |
| 3 | 122011220101120121112210000010 |
| 4 | 131302211321320003000200 |
| 5 | 114133113001124200000 |
| 6 | 1142353433415324520 |
| 7 | 36411612200411055 |
| oct | 3562457170030040 |
| 9 | 564811517483003 |
| 10 | 131020022100000 |
| 11 | 38824308877200 |
| 12 | 12840684380740 |
| 13 | 581519a995877 |
| 14 | 244d58d80102c |
| 15 | 10231e8993d50 |
| hex | 772979e03020 |
131020022100000 has 1296 divisors, whose sum is σ = 494024594277312. Its totient is φ = 30377001600000.
The previous prime is 131020022099999. The next prime is 131020022100001. The reversal of 131020022100000 is 1220020131.
It is an interprime number because it is at equal distance from previous prime (131020022099999) and next prime (131020022100001).
It is a super-3 number, since 3×1310200221000003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is not an unprimeable number, because it can be changed into a prime (131020022100001) by changing a digit.
It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 19202696589 + ... + 19202703411.
It is an arithmetic number, because the mean of its divisors is an integer number (381191816572).
Almost surely, 2131020022100000 is an apocalyptic number.
131020022100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131020022100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (247012297138656).
131020022100000 is an abundant number, since it is smaller than the sum of its proper divisors (363004572177312).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131020022100000 is an equidigital number, since it uses as much as digits as its factorization.
131020022100000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6929 (or 6867 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 131020022100000 its reverse (1220020131), we get a palindrome (131021242120131).
The spelling of 131020022100000 in words is "one hundred thirty-one trillion, twenty billion, twenty-two million, one hundred thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •