Base | Representation |
---|---|
bin | 11000011001111000… |
… | …01100111010010011 |
3 | 1020211002202001212202 |
4 | 30030330030322103 |
5 | 203313103310003 |
6 | 10004033313415 |
7 | 642452150615 |
oct | 141474147223 |
9 | 36732661782 |
10 | 13102010003 |
11 | 561381a045 |
12 | 2657a0586b |
13 | 130a56a354 |
14 | 8c4120db5 |
15 | 51a3a2088 |
hex | 30cf0ce93 |
13102010003 has 2 divisors, whose sum is σ = 13102010004. Its totient is φ = 13102010002.
The previous prime is 13102009981. The next prime is 13102010039. The reversal of 13102010003 is 30001020131.
13102010003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30001020131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13102010003 - 210 = 13102008979 is a prime.
It is a super-2 number, since 2×131020100032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13102010203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551005001 + 6551005002.
It is an arithmetic number, because the mean of its divisors is an integer number (6551005002).
Almost surely, 213102010003 is an apocalyptic number.
13102010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102010003 is an equidigital number, since it uses as much as digits as its factorization.
13102010003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 13102010003 its reverse (30001020131), we get a palindrome (43103030134).
The spelling of 13102010003 in words is "thirteen billion, one hundred two million, ten thousand, three".
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