Base | Representation |
---|---|
bin | 11000011001111000… |
… | …01111011001110101 |
3 | 1020211002202120212220 |
4 | 30030330033121311 |
5 | 203313104121323 |
6 | 10004033432553 |
7 | 642452222442 |
oct | 141474173165 |
9 | 36732676786 |
10 | 13102020213 |
11 | 5613826787 |
12 | 2657a0b759 |
13 | 130a571ba9 |
14 | 8c41249c9 |
15 | 51a3a50e3 |
hex | 30cf0f675 |
13102020213 has 8 divisors (see below), whose sum is σ = 17472151008. Its totient is φ = 8733284784.
The previous prime is 13102020187. The next prime is 13102020221. The reversal of 13102020213 is 31202020131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13102020213 - 224 = 13085242997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102020192 and 13102020201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102020263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 326731 + ... + 364632.
It is an arithmetic number, because the mean of its divisors is an integer number (2184018876).
Almost surely, 213102020213 is an apocalyptic number.
It is an amenable number.
13102020213 is a deficient number, since it is larger than the sum of its proper divisors (4370130795).
13102020213 is an equidigital number, since it uses as much as digits as its factorization.
13102020213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 697683.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13102020213 its reverse (31202020131), we get a palindrome (44304040344).
The spelling of 13102020213 in words is "thirteen billion, one hundred two million, twenty thousand, two hundred thirteen".
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