Base | Representation |
---|---|
bin | 11101110010100110000110… |
… | …010010010110011110110111 |
3 | 122011220102010010100120000212 |
4 | 131302212012102112132313 |
5 | 114133113412430301403 |
6 | 1142353510214300035 |
7 | 36411620306311433 |
oct | 3562460622263667 |
9 | 564812103316025 |
10 | 131020230322103 |
11 | 38824405365591 |
12 | 1284072205761b |
13 | 5815201b6b405 |
14 | 244d5ad3239c3 |
15 | 102320bdc44d8 |
hex | 7729864967b7 |
131020230322103 has 2 divisors, whose sum is σ = 131020230322104. Its totient is φ = 131020230322102.
The previous prime is 131020230322099. The next prime is 131020230322123. The reversal of 131020230322103 is 301223032020131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131020230322103 - 22 = 131020230322099 is a prime.
It is a super-2 number, since 2×1310202303221032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131020230322123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510115161051 + 65510115161052.
It is an arithmetic number, because the mean of its divisors is an integer number (65510115161052).
Almost surely, 2131020230322103 is an apocalyptic number.
131020230322103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020230322103 is an equidigital number, since it uses as much as digits as its factorization.
131020230322103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131020230322103 its reverse (301223032020131), we get a palindrome (432243262342234).
The spelling of 131020230322103 in words is "one hundred thirty-one trillion, twenty billion, two hundred thirty million, three hundred twenty-two thousand, one hundred three".
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