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131020230322103 is a prime number
BaseRepresentation
bin11101110010100110000110…
…010010010110011110110111
3122011220102010010100120000212
4131302212012102112132313
5114133113412430301403
61142353510214300035
736411620306311433
oct3562460622263667
9564812103316025
10131020230322103
1138824405365591
121284072205761b
135815201b6b405
14244d5ad3239c3
15102320bdc44d8
hex7729864967b7

131020230322103 has 2 divisors, whose sum is σ = 131020230322104. Its totient is φ = 131020230322102.

The previous prime is 131020230322099. The next prime is 131020230322123. The reversal of 131020230322103 is 301223032020131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131020230322103 - 22 = 131020230322099 is a prime.

It is a super-2 number, since 2×1310202303221032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020230322123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510115161051 + 65510115161052.

It is an arithmetic number, because the mean of its divisors is an integer number (65510115161052).

Almost surely, 2131020230322103 is an apocalyptic number.

131020230322103 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020230322103 is an equidigital number, since it uses as much as digits as its factorization.

131020230322103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 131020230322103 its reverse (301223032020131), we get a palindrome (432243262342234).

The spelling of 131020230322103 in words is "one hundred thirty-one trillion, twenty billion, two hundred thirty million, three hundred twenty-two thousand, one hundred three".