Base | Representation |
---|---|
bin | 10011000100001110010… |
… | …000001001100111100001 |
3 | 11122020212101020110210022 |
4 | 103010032100021213201 |
5 | 132431244224440001 |
6 | 2441522141443225 |
7 | 163442036302601 |
oct | 23041620114741 |
9 | 4566771213708 |
10 | 1310204140001 |
11 | 465722097649 |
12 | 191b14870515 |
13 | 9672318b3c3 |
14 | 475b288ac01 |
15 | 24134ba911b |
hex | 1310e4099e1 |
1310204140001 has 2 divisors, whose sum is σ = 1310204140002. Its totient is φ = 1310204140000.
The previous prime is 1310204139997. The next prime is 1310204140093. The reversal of 1310204140001 is 1000414020131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1295326239376 + 14877900625 = 1138124^2 + 121975^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310204140001 - 22 = 1310204139997 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310204145001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655102070000 + 655102070001.
It is an arithmetic number, because the mean of its divisors is an integer number (655102070001).
Almost surely, 21310204140001 is an apocalyptic number.
It is an amenable number.
1310204140001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310204140001 is an equidigital number, since it uses as much as digits as its factorization.
1310204140001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1310204140001 its reverse (1000414020131), we get a palindrome (2310618160132).
The spelling of 1310204140001 in words is "one trillion, three hundred ten billion, two hundred four million, one hundred forty thousand, one".
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