13102103123113 has 4 divisors (see below), whose sum is σ = 13102352137360. Its totient is φ = 13101854108868.

The previous prime is 13102103123077. The next prime is 13102103123159. The reversal of 13102103123113 is 31132130120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102103123113 - 2²⁵ = 13102069568681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102103123513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124428183 + ... + 124533436.

It is an arithmetic number, because the mean of its divisors is an integer number (3275588034340).

Almost surely, 2^{13102103123113} is an apocalyptic number.

It is an amenable number.

13102103123113 is a deficient number, since it is larger than the sum of its proper divisors (249014247).

13102103123113 is an equidigital number, since it uses as much as digits as its factorization.

13102103123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249014246.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 13102103123113 its reverse (31132130120131), we get a palindrome (44234233243244).

The spelling of 13102103123113 in words is "thirteen trillion, one hundred two billion, one hundred three million, one hundred twenty-three thousand, one hundred thirteen".