131021143324340 has 48 divisors (see below), whose sum is σ = 284635595538000. Its totient is φ = 50600654641152.

The previous prime is 131021143324339. The next prime is 131021143324349. The reversal of 131021143324340 is 43423341120131.

It can be written as a sum of positive squares in 8 ways, for example, as 7673553733924 + 123347589590416 = 2770118^2 + 11106196^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131021143324297 and 131021143324306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131021143324349) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47957486 + ... + 50615834.

It is an arithmetic number, because the mean of its divisors is an integer number (5929908240375).

Almost surely, 2^{131021143324340} is an apocalyptic number.

131021143324340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131021143324340 is an abundant number, since it is smaller than the sum of its proper divisors (153614452213660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021143324340 is a wasteful number, since it uses less digits than its factorization.

131021143324340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2743364 (or 2743362 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131021143324340 its reverse (43423341120131), we get a palindrome (174444484444471).

The spelling of 131021143324340 in words is "one hundred thirty-one trillion, twenty-one billion, one hundred forty-three million, three hundred twenty-four thousand, three hundred forty".