13102120320301 has 4 divisors (see below), whose sum is σ = 13154320003104. Its totient is φ = 13049920637500.

The previous prime is 13102120320287. The next prime is 13102120320329. The reversal of 13102120320301 is 10302302120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102120320301 - 2¹⁵ = 13102120287533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102120380301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26099841025 + ... + 26099841526.

It is an arithmetic number, because the mean of its divisors is an integer number (3288580000776).

Almost surely, 2^{13102120320301} is an apocalyptic number.

It is an amenable number.

13102120320301 is a deficient number, since it is larger than the sum of its proper divisors (52199682803).

13102120320301 is an equidigital number, since it uses as much as digits as its factorization.

13102120320301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52199682802.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13102120320301 its reverse (10302302120131), we get a palindrome (23404422440432).

The spelling of 13102120320301 in words is "thirteen trillion, one hundred two billion, one hundred twenty million, three hundred twenty thousand, three hundred one".