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131021211211022 = 2115955509600501
BaseRepresentation
bin11101110010100111000000…
…110000001001010100001110
3122011220111122111001212200002
4131302213000300021110032
5114133122420032223042
61142354151414204302
736411653516605046
oct3562470060112416
9564814574055602
10131021211211022
1138824869015990
1212840956653692
13581532a146962
14244d6636d8726
15102326807d132
hex7729c0c0950e

131021211211022 has 8 divisors (see below), whose sum is σ = 214398345618072. Its totient is φ = 59555096005000.

The previous prime is 131021211210983. The next prime is 131021211211127. The reversal of 131021211211022 is 220112112120131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131021211210985 and 131021211211003.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2977754800229 + ... + 2977754800272.

It is an arithmetic number, because the mean of its divisors is an integer number (26799793202259).

Almost surely, 2131021211211022 is an apocalyptic number.

131021211211022 is a deficient number, since it is larger than the sum of its proper divisors (83377134407050).

131021211211022 is a wasteful number, since it uses less digits than its factorization.

131021211211022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5955509600514.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 131021211211022 its reverse (220112112120131), we get a palindrome (351133323331153).

The spelling of 131021211211022 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred eleven million, two hundred eleven thousand, twenty-two".

Divisors: 1 2 11 22 5955509600501 11911019201002 65510605605511 131021211211022