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1310213030111 = 2945179759659
BaseRepresentation
bin10011000100001110110…
…010000100000011011111
311122020212222222010201122
4103010032302010003133
5132431304013430421
62441523100201155
7163442205000356
oct23041662040337
94566788863648
101310213030111
11465727109947
12191b178391bb
1396724c81a1b
14475b3b2299d
15241358632ab
hex1310ec840df

1310213030111 has 4 divisors (see below), whose sum is σ = 1355392789800. Its totient is φ = 1265033270424.

The previous prime is 1310213030101. The next prime is 1310213030131. The reversal of 1310213030111 is 1110303120131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310213030111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1310213030111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310213030101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22589879801 + ... + 22589879858.

It is an arithmetic number, because the mean of its divisors is an integer number (338848197450).

Almost surely, 21310213030111 is an apocalyptic number.

1310213030111 is a deficient number, since it is larger than the sum of its proper divisors (45179759689).

1310213030111 is an equidigital number, since it uses as much as digits as its factorization.

1310213030111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45179759688.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1310213030111 its reverse (1110303120131), we get a palindrome (2420516150242).

The spelling of 1310213030111 in words is "one trillion, three hundred ten billion, two hundred thirteen million, thirty thousand, one hundred eleven".

Divisors: 1 29 45179759659 1310213030111