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131021315 = 526204263
BaseRepresentation
bin1111100111100…
…11101000000011
3100010112120110022
413303303220003
5232020140230
621000124055
73150443225
oct763635003
9303476408
10131021315
1167a5a287
1237a6662b
13211b5609
1413588415
15b7811e5
hex7cf3a03

131021315 has 4 divisors (see below), whose sum is σ = 157225584. Its totient is φ = 104817048.

The previous prime is 131021311. The next prime is 131021323. The reversal of 131021315 is 513120131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131021315 - 22 = 131021311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131021293 and 131021302.

It is not an unprimeable number, because it can be changed into a prime (131021311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13102127 + ... + 13102136.

It is an arithmetic number, because the mean of its divisors is an integer number (39306396).

Almost surely, 2131021315 is an apocalyptic number.

131021315 is a deficient number, since it is larger than the sum of its proper divisors (26204269).

131021315 is an equidigital number, since it uses as much as digits as its factorization.

131021315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26204268.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 131021315 is about 11446.4542544842. The cubic root of 131021315 is about 507.9028517703.

Adding to 131021315 its reverse (513120131), we get a palindrome (644141446).

The spelling of 131021315 in words is "one hundred thirty-one million, twenty-one thousand, three hundred fifteen".

Divisors: 1 5 26204263 131021315