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1310214220124 = 22582156271011
BaseRepresentation
bin10011000100001110110…
…110100110100101011100
311122020220002012121010012
4103010032312212211130
5132431304320020444
62441523141502352
7163442221054655
oct23041666464534
94566802177105
101310214220124
11465727851a27
12191b181119b8
13967252aa584
14475b3d5252c
15241359eab9e
hex1310eda695c

1310214220124 has 12 divisors (see below), whose sum is σ = 2293268823048. Its totient is φ = 654994556400.

The previous prime is 1310214220103. The next prime is 1310214220151. The reversal of 1310214220124 is 4210224120131.

It is a super-2 number, since 2×13102142201242 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310214220124.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28112222 + ... + 28158789.

It is an arithmetic number, because the mean of its divisors is an integer number (191105735254).

Almost surely, 21310214220124 is an apocalyptic number.

It is an amenable number.

1310214220124 is a deficient number, since it is larger than the sum of its proper divisors (983054602924).

1310214220124 is a wasteful number, since it uses less digits than its factorization.

1310214220124 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56276836 (or 56276834 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1310214220124 its reverse (4210224120131), we get a palindrome (5520438340255).

The spelling of 1310214220124 in words is "one trillion, three hundred ten billion, two hundred fourteen million, two hundred twenty thousand, one hundred twenty-four".

Divisors: 1 2 4 5821 11642 23284 56271011 112542022 225084044 327553555031 655107110062 1310214220124