Base | Representation |
---|---|
bin | 111101000000110000… |
… | …1010001111110000101 |
3 | 110112012011000102200120 |
4 | 1322001201101332011 |
5 | 4121313113112401 |
6 | 140105104132153 |
7 | 12315563442102 |
oct | 1720141217605 |
9 | 415164012616 |
10 | 131022004101 |
11 | 50625561a1a |
12 | 21487007059 |
13 | c4808473a1 |
14 | 64ad103aa9 |
15 | 361c93e836 |
hex | 1e81851f85 |
131022004101 has 4 divisors (see below), whose sum is σ = 174696005472. Its totient is φ = 87348002732.
The previous prime is 131022004073. The next prime is 131022004103. The reversal of 131022004101 is 101400220131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131022004101 - 29 = 131022003589 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131022004103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21837000681 + ... + 21837000686.
It is an arithmetic number, because the mean of its divisors is an integer number (43674001368).
Almost surely, 2131022004101 is an apocalyptic number.
It is an amenable number.
131022004101 is a deficient number, since it is larger than the sum of its proper divisors (43674001371).
131022004101 is an equidigital number, since it uses as much as digits as its factorization.
131022004101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43674001370.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 131022004101 its reverse (101400220131), we get a palindrome (232422224232).
The spelling of 131022004101 in words is "one hundred thirty-one billion, twenty-two million, four thousand, one hundred one".
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