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1310220113231 is a prime number
BaseRepresentation
bin10011000100001111001…
…101000101010101001111
311122020220111021222221102
4103010033031011111033
5132431312322110411
62441523512053315
7163442322131021
oct23041715052517
94566814258842
101310220113231
11465730107567
12191b1a09423b
1396726591a13
14475b4a48011
15241362b1d3b
hex1310f34554f

1310220113231 has 2 divisors, whose sum is σ = 1310220113232. Its totient is φ = 1310220113230.

The previous prime is 1310220113227. The next prime is 1310220113249. The reversal of 1310220113231 is 1323110220131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310220113231 - 22 = 1310220113227 is a prime.

It is a super-4 number, since 4×13102201132314 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310220113731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655110056615 + 655110056616.

It is an arithmetic number, because the mean of its divisors is an integer number (655110056616).

Almost surely, 21310220113231 is an apocalyptic number.

1310220113231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310220113231 is an equidigital number, since it uses as much as digits as its factorization.

1310220113231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1310220113231 its reverse (1323110220131), we get a palindrome (2633330333362).

The spelling of 1310220113231 in words is "one trillion, three hundred ten billion, two hundred twenty million, one hundred thirteen thousand, two hundred thirty-one".