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13102202221103 = 35944071828127
BaseRepresentation
bin1011111010101001100000…
…0110111111001000101111
31201101120002000000021221202
42332222120012333020233
53204131302232033403
643511022452520115
72521413533216522
oct276523006771057
951346060007852
1013102202221103
1141a1681642136
12157736502003b
137406bc7c6468
14334215740bb9
1517ac41dcb688
hexbea981bf22f

13102202221103 has 8 divisors (see below), whose sum is σ = 13139012597760. Its totient is φ = 13065393589560.

The previous prime is 13102202221061. The next prime is 13102202221127. The reversal of 13102202221103 is 30112220220131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13102202221103 - 218 = 13102201958959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102202221183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15407426 + ... + 16235552.

It is an arithmetic number, because the mean of its divisors is an integer number (1642376574720).

Almost surely, 213102202221103 is an apocalyptic number.

13102202221103 is a deficient number, since it is larger than the sum of its proper divisors (36810376657).

13102202221103 is an equidigital number, since it uses as much as digits as its factorization.

13102202221103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 872557.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13102202221103 its reverse (30112220220131), we get a palindrome (43214422441234).

The spelling of 13102202221103 in words is "thirteen trillion, one hundred two billion, two hundred two million, two hundred twenty-one thousand, one hundred three".

Divisors: 1 359 44071 828127 15821489 297297593 36496385017 13102202221103