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13102203130003 = 131007861779231
BaseRepresentation
bin1011111010101001100000…
…1010011101000010010011
31201101120002001201110201201
42332222120022131002103
53204131303000130003
643511022524212031
72521413544023421
oct276523012350223
951346061643651
1013102203130003
1141a1682102a99
12157736539a017
137406bca54080
143342158da111
1517ac4200ab1d
hexbea9829d093

13102203130003 has 4 divisors (see below), whose sum is σ = 14110064909248. Its totient is φ = 12094341350760.

The previous prime is 13102203129919. The next prime is 13102203130007. The reversal of 13102203130003 is 30003130220131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13102203130003 - 225 = 13102169575571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102203130007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503930889603 + ... + 503930889628.

It is an arithmetic number, because the mean of its divisors is an integer number (3527516227312).

Almost surely, 213102203130003 is an apocalyptic number.

13102203130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13102203130003 is a deficient number, since it is larger than the sum of its proper divisors (1007861779245).

13102203130003 is a wasteful number, since it uses less digits than its factorization.

13102203130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1007861779244.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13102203130003 its reverse (30003130220131), we get a palindrome (43105333350134).

The spelling of 13102203130003 in words is "thirteen trillion, one hundred two billion, two hundred three million, one hundred thirty thousand, three".

Divisors: 1 13 1007861779231 13102203130003