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131022111001 = 196895900579
BaseRepresentation
bin111101000000110000…
…1101100000100011001
3110112012011012212022211
41322001201230010121
54121313130023001
6140105110315121
712315564365545
oct1720141540431
9415164185284
10131022111001
1150625625271
1221487058aa1
13c480883c42
1464ad130a25
15361c961351
hex1e8186c119

131022111001 has 4 divisors (see below), whose sum is σ = 137918011600. Its totient is φ = 124126210404.

The previous prime is 131022110993. The next prime is 131022111007. The reversal of 131022111001 is 100111220131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131022111001 - 23 = 131022110993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131022111007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3447950271 + ... + 3447950308.

It is an arithmetic number, because the mean of its divisors is an integer number (34479502900).

Almost surely, 2131022111001 is an apocalyptic number.

It is an amenable number.

131022111001 is a deficient number, since it is larger than the sum of its proper divisors (6895900599).

131022111001 is an equidigital number, since it uses as much as digits as its factorization.

131022111001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6895900598.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 131022111001 its reverse (100111220131), we get a palindrome (231133331132).

The spelling of 131022111001 in words is "one hundred thirty-one billion, twenty-two million, one hundred eleven thousand, one".

Divisors: 1 19 6895900579 131022111001