Base | Representation |
---|---|
bin | 1011111010101001100010… |
… | …1001010100000111110111 |
3 | 1201101120002121221111001201 |
4 | 2332222120221110013313 |
5 | 3204131312033014314 |
6 | 43511023413433331 |
7 | 2521414002546331 |
oct | 276523051240767 |
9 | 51346077844051 |
10 | 13102211219959 |
11 | 41a1686729104 |
12 | 157736803b847 |
13 | 7406c1627424 |
14 | 334216a04451 |
15 | 17ac42aa7b74 |
hex | bea98a541f7 |
13102211219959 has 2 divisors, whose sum is σ = 13102211219960. Its totient is φ = 13102211219958.
The previous prime is 13102211219957. The next prime is 13102211220029. The reversal of 13102211219959 is 95991211220131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13102211219959 - 21 = 13102211219957 is a prime.
Together with 13102211219957, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102211219957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551105609979 + 6551105609980.
It is an arithmetic number, because the mean of its divisors is an integer number (6551105609980).
Almost surely, 213102211219959 is an apocalyptic number.
13102211219959 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102211219959 is an equidigital number, since it uses as much as digits as its factorization.
13102211219959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 87480, while the sum is 46.
The spelling of 13102211219959 in words is "thirteen trillion, one hundred two billion, two hundred eleven million, two hundred nineteen thousand, nine hundred fifty-nine".
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