Base | Representation |
---|---|
bin | 1011111010101001100100… |
… | …1111100000011111110101 |
3 | 1201101120010022210011011101 |
4 | 2332222121033200133311 |
5 | 3204131322113411432 |
6 | 43511024412210101 |
7 | 2521414153626313 |
oct | 276523117403765 |
9 | 51346108704141 |
10 | 13102221232117 |
11 | 41a1691347416 |
12 | 157736b469931 |
13 | 7406c3721694 |
14 | 33421808d0b3 |
15 | 17ac438d44e7 |
hex | bea993e07f5 |
13102221232117 has 2 divisors, whose sum is σ = 13102221232118. Its totient is φ = 13102221232116.
The previous prime is 13102221231991. The next prime is 13102221232151. The reversal of 13102221232117 is 71123212220131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9506529226756 + 3595692005361 = 3083266^2 + 1896231^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102221232117 - 211 = 13102221230069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102221232157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551110616058 + 6551110616059.
It is an arithmetic number, because the mean of its divisors is an integer number (6551110616059).
Almost surely, 213102221232117 is an apocalyptic number.
It is an amenable number.
13102221232117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102221232117 is an equidigital number, since it uses as much as digits as its factorization.
13102221232117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 13102221232117 its reverse (71123212220131), we get a palindrome (84225433452248).
The spelling of 13102221232117 in words is "thirteen trillion, one hundred two billion, two hundred twenty-one million, two hundred thirty-two thousand, one hundred seventeen".
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