13102222131133 has 4 divisors (see below), whose sum is σ = 13102232935068. Its totient is φ = 13102211327200.

The previous prime is 13102222131007. The next prime is 13102222131151. The reversal of 13102222131133 is 33113122220131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 5689355546169 + 7412866584964 = 2385237^2 + 2722658^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102222131133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102222131098 and 13102222131107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102222131533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3313816 + ... + 6098017.

It is an arithmetic number, because the mean of its divisors is an integer number (3275558233767).

Almost surely, 2^{13102222131133} is an apocalyptic number.

It is an amenable number.

13102222131133 is a deficient number, since it is larger than the sum of its proper divisors (10803935).

13102222131133 is an equidigital number, since it uses as much as digits as its factorization.

13102222131133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10803934.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13102222131133 its reverse (33113122220131), we get a palindrome (46215344351264).

The spelling of 13102222131133 in words is "thirteen trillion, one hundred two billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred thirty-three".