Search a number
-
+
131022313200 = 2432522937107317
BaseRepresentation
bin111101000000110001…
…0011101011011110000
3110112012011121010200200
41322001202131123300
54121313203010300
6140105114515200
712315566200212
oct1720142353360
9415164533620
10131022313200
1150625753179
1221487135b00
13c480924c9c
1464ad1845b2
15361c9a1200
hex1e8189d6f0

131022313200 has 720 divisors, whose sum is σ = 489127934880. Its totient is φ = 32413409280.

The previous prime is 131022313151. The next prime is 131022313231. The reversal of 131022313200 is 2313220131.

131022313200 is a `hidden beast` number, since 1 + 310 + 2 + 2 + 31 + 320 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 413319442 + ... + 413319758.

It is an arithmetic number, because the mean of its divisors is an integer number (679344354).

Almost surely, 2131022313200 is an apocalyptic number.

131022313200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131022313200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (244563967440).

131022313200 is an abundant number, since it is smaller than the sum of its proper divisors (358105621680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131022313200 is a wasteful number, since it uses less digits than its factorization.

131022313200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 514 (or 500 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 131022313200 its reverse (2313220131), we get a palindrome (133335533331).

The spelling of 131022313200 in words is "one hundred thirty-one billion, twenty-two million, three hundred thirteen thousand, two hundred".