Base | Representation |
---|---|
bin | 111101000000110001… |
… | …0100010000011101111 |
3 | 110112012011122002200021 |
4 | 1322001202202003233 |
5 | 4121313204112033 |
6 | 140105115143011 |
7 | 12315566306353 |
oct | 1720142420357 |
9 | 415164562607 |
10 | 131022332143 |
11 | 5062576642a |
12 | 21487144a67 |
13 | c4809307b1 |
14 | 64ad18b463 |
15 | 361c9a6b2d |
hex | 1e818a20ef |
131022332143 has 2 divisors, whose sum is σ = 131022332144. Its totient is φ = 131022332142.
The previous prime is 131022332057. The next prime is 131022332171. The reversal of 131022332143 is 341233220131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131022332143 - 213 = 131022323951 is a prime.
It is a super-2 number, since 2×1310223321432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131022332743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511166071 + 65511166072.
It is an arithmetic number, because the mean of its divisors is an integer number (65511166072).
Almost surely, 2131022332143 is an apocalyptic number.
131022332143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022332143 is an equidigital number, since it uses as much as digits as its factorization.
131022332143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131022332143 its reverse (341233220131), we get a palindrome (472255552274).
The spelling of 131022332143 in words is "one hundred thirty-one billion, twenty-two million, three hundred thirty-two thousand, one hundred forty-three".
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