Base | Representation |
---|---|
bin | 11101110010101000001111… |
… | …100111110001000001000000 |
3 | 122011220122001200220120110121 |
4 | 131302220033213301001000 |
5 | 114133133122302230100 |
6 | 1142354531003110024 |
7 | 36412031354625616 |
oct | 3562501747610100 |
9 | 564818050816417 |
10 | 131022534414400 |
11 | 38825387a211a2 |
12 | 12841065812314 |
13 | 58154ab317135 |
14 | 244d74b3396b6 |
15 | 10232e430351a |
hex | 772a0f9f1040 |
131022534414400 has 42 divisors (see below), whose sum is σ = 322397323747370. Its totient is φ = 52409013765120.
The previous prime is 131022534414383. The next prime is 131022534414433. The reversal of 131022534414400 is 4414435220131.
It can be written as a sum of positive squares in 3 ways, for example, as 22667425705024 + 108355108709376 = 4761032^2 + 10409376^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 40944540405 + ... + 40944543604.
Almost surely, 2131022534414400 is an apocalyptic number.
131022534414400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131022534414400 is an abundant number, since it is smaller than the sum of its proper divisors (191374789332970).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131022534414400 is an equidigital number, since it uses as much as digits as its factorization.
131022534414400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81889084031 (or 81889084016 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 131022534414400 its reverse (4414435220131), we get a palindrome (135436969634531).
The spelling of 131022534414400 in words is "one hundred thirty-one trillion, twenty-two billion, five hundred thirty-four million, four hundred fourteen thousand, four hundred".
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