Base | Representation |
---|---|
bin | 111101000000110011… |
… | …0010101101010111011 |
3 | 110112012020111210110011 |
4 | 1322001212111222323 |
5 | 4121313433024404 |
6 | 140105152402351 |
7 | 12315610633453 |
oct | 1720146255273 |
9 | 415166453404 |
10 | 131023329979 |
11 | 50626288093 |
12 | 214875463b7 |
13 | c480bbca29 |
14 | 64ad36ad63 |
15 | 361cb02604 |
hex | 1e81995abb |
131023329979 has 2 divisors, whose sum is σ = 131023329980. Its totient is φ = 131023329978.
The previous prime is 131023329977. The next prime is 131023329989. The reversal of 131023329979 is 979923320131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131023329979 - 21 = 131023329977 is a prime.
It is a super-2 number, since 2×1310233299792 (a number of 23 digits) contains 22 as substring.
Together with 131023329977, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131023329977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511664989 + 65511664990.
It is an arithmetic number, because the mean of its divisors is an integer number (65511664990).
Almost surely, 2131023329979 is an apocalyptic number.
131023329979 is a deficient number, since it is larger than the sum of its proper divisors (1).
131023329979 is an equidigital number, since it uses as much as digits as its factorization.
131023329979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 551124, while the sum is 49.
The spelling of 131023329979 in words is "one hundred thirty-one billion, twenty-three million, three hundred twenty-nine thousand, nine hundred seventy-nine".
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