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1310233305055 = 5292311589371
BaseRepresentation
bin10011000100001111111…
…111011001111111011111
311122020221102010012201111
4103010033333121333133
5132431324211230210
62441525102522451
7163442542223113
oct23041777317737
94566842105644
101310233305055
114657375a77a4
12191b22596427
139672923032c
14475b66bd743
152413751a88a
hex1310ffd9fdf

1310233305055 has 12 divisors (see below), whose sum is σ = 1628366058072. Its totient is φ = 1012042273760.

The previous prime is 1310233305023. The next prime is 1310233305067. The reversal of 1310233305055 is 5505033320131.

It is not a de Polignac number, because 1310233305055 - 25 = 1310233305023 is a prime.

It is a super-2 number, since 2×13102333050552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 155790481 + ... + 155798890.

It is an arithmetic number, because the mean of its divisors is an integer number (135697171506).

Almost surely, 21310233305055 is an apocalyptic number.

1310233305055 is a deficient number, since it is larger than the sum of its proper divisors (318132753017).

1310233305055 is an equidigital number, since it uses as much as digits as its factorization.

1310233305055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 311589434 (or 311589405 counting only the distinct ones).

The product of its (nonzero) digits is 20250, while the sum is 31.

Adding to 1310233305055 its reverse (5505033320131), we get a palindrome (6815266625186).

The spelling of 1310233305055 in words is "one trillion, three hundred ten billion, two hundred thirty-three million, three hundred five thousand, fifty-five".

Divisors: 1 5 29 145 841 4205 311589371 1557946855 9036091759 45180458795 262046661011 1310233305055