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131023331003 = 1011297260703
BaseRepresentation
bin111101000000110011…
…0010101111010111011
3110112012020111211212002
41322001212111322323
54121313433043003
6140105152411215
712315610636445
oct1720146257273
9415166454762
10131023331003
1150626288934
1221487546b0b
13c480bc0336
1464ad36b495
15361cb02a88
hex1e81995ebb

131023331003 has 4 divisors (see below), whose sum is σ = 132320591808. Its totient is φ = 129726070200.

The previous prime is 131023330951. The next prime is 131023331017. The reversal of 131023331003 is 300133320131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131023331003 - 210 = 131023329979 is a prime.

It is a super-2 number, since 2×1310233310032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131023331203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648630251 + ... + 648630452.

It is an arithmetic number, because the mean of its divisors is an integer number (33080147952).

Almost surely, 2131023331003 is an apocalyptic number.

131023331003 is a deficient number, since it is larger than the sum of its proper divisors (1297260805).

131023331003 is a wasteful number, since it uses less digits than its factorization.

131023331003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1297260804.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 131023331003 its reverse (300133320131), we get a palindrome (431156651134).

The spelling of 131023331003 in words is "one hundred thirty-one billion, twenty-three million, three hundred thirty-one thousand, three".

Divisors: 1 101 1297260703 131023331003