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131024242127 is a prime number
BaseRepresentation
bin111101000000110100…
…1110100010111001111
3110112012022020010200102
41322001221310113033
54121314201222002
6140105224121315
712315621453002
oct1720151642717
9415168203612
10131024242127
1150626850429
122148790623b
13c48114bc6c
1464ad527539
15361cc32a02
hex1e81a745cf

131024242127 has 2 divisors, whose sum is σ = 131024242128. Its totient is φ = 131024242126.

The previous prime is 131024242093. The next prime is 131024242177. The reversal of 131024242127 is 721242420131.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (721242420131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131024242127 - 212 = 131024238031 is a prime.

It is a super-3 number, since 3×1310242421273 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131024242127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131024242177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65512121063 + 65512121064.

It is an arithmetic number, because the mean of its divisors is an integer number (65512121064).

Almost surely, 2131024242127 is an apocalyptic number.

131024242127 is a deficient number, since it is larger than the sum of its proper divisors (1).

131024242127 is an equidigital number, since it uses as much as digits as its factorization.

131024242127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 131024242127 its reverse (721242420131), we get a palindrome (852266662258).

The spelling of 131024242127 in words is "one hundred thirty-one billion, twenty-four million, two hundred forty-two thousand, one hundred twenty-seven".