Base | Representation |
---|---|
bin | 111101000000110111… |
… | …0101000010011000111 |
3 | 110112012101121012212101 |
4 | 1322001232220103013 |
5 | 4121320012102211 |
6 | 140105311132531 |
7 | 12315635255164 |
oct | 1720156502307 |
9 | 415171535771 |
10 | 131025503431 |
11 | 50627532029 |
12 | 21488214147 |
13 | c4814a10b4 |
14 | 64ad77506b |
15 | 361cdd15c1 |
hex | 1e81ba84c7 |
131025503431 has 2 divisors, whose sum is σ = 131025503432. Its totient is φ = 131025503430.
The previous prime is 131025503423. The next prime is 131025503449. The reversal of 131025503431 is 134305520131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (134305520131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131025503431 - 23 = 131025503423 is a prime.
It is a super-2 number, since 2×1310255034312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131025503431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131025503471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65512751715 + 65512751716.
It is an arithmetic number, because the mean of its divisors is an integer number (65512751716).
Almost surely, 2131025503431 is an apocalyptic number.
131025503431 is a deficient number, since it is larger than the sum of its proper divisors (1).
131025503431 is an equidigital number, since it uses as much as digits as its factorization.
131025503431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 131025503431 in words is "one hundred thirty-one billion, twenty-five million, five hundred three thousand, four hundred thirty-one".
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