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13103000113 = 73160382489
BaseRepresentation
bin11000011001111111…
…11110101000110001
31020211011121101001111
430030333332220301
5203313332000423
610004110433321
7642463443340
oct141477765061
936734541044
1013103000113
115614335a15
122658202841
13130a825c08
148c42dbb57
1551a4ea60d
hex30cffea31

13103000113 has 8 divisors (see below), whose sum is σ = 15457917440. Its totient is φ = 10868847840.

The previous prime is 13103000107. The next prime is 13103000117. The reversal of 13103000113 is 31100030131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13103000113 - 225 = 13069445681 is a prime.

It is a super-2 number, since 2×131030001132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13103000093 and 13103000102.

It is not an unprimeable number, because it can be changed into a prime (13103000117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30191028 + ... + 30191461.

It is an arithmetic number, because the mean of its divisors is an integer number (1932239680).

Almost surely, 213103000113 is an apocalyptic number.

It is an amenable number.

13103000113 is a deficient number, since it is larger than the sum of its proper divisors (2354917327).

13103000113 is an equidigital number, since it uses as much as digits as its factorization.

13103000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60382527.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 13103000113 its reverse (31100030131), we get a palindrome (44203030244).

The spelling of 13103000113 in words is "thirteen billion, one hundred three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 7 31 217 60382489 422677423 1871857159 13103000113