Base | Representation |
---|---|
bin | 11101110010101111001101… |
… | …010101010111101000000111 |
3 | 122011221100100211201222020112 |
4 | 131302233031111113220013 |
5 | 114133243431112331101 |
6 | 1142402205010423235 |
7 | 36412414565204666 |
oct | 3562571525275007 |
9 | 564840324658215 |
10 | 131030012230151 |
11 | 38828574a5a911 |
12 | 128425b1b91b1b |
13 | 5816100608798 |
14 | 244dc5a514ddd |
15 | 10235d0a526bb |
hex | 772bcd557a07 |
131030012230151 has 2 divisors, whose sum is σ = 131030012230152. Its totient is φ = 131030012230150.
The previous prime is 131030012230133. The next prime is 131030012230291. The reversal of 131030012230151 is 151032210030131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131030012230151 - 242 = 126631965719047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131030012230651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515006115075 + 65515006115076.
It is an arithmetic number, because the mean of its divisors is an integer number (65515006115076).
Almost surely, 2131030012230151 is an apocalyptic number.
131030012230151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030012230151 is an equidigital number, since it uses as much as digits as its factorization.
131030012230151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 131030012230151 its reverse (151032210030131), we get a palindrome (282062222260282).
The spelling of 131030012230151 in words is "one hundred thirty-one trillion, thirty billion, twelve million, two hundred thirty thousand, one hundred fifty-one".
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