13103011313 has 4 divisors (see below), whose sum is σ = 14974870080. Its totient is φ = 11231152548.

The previous prime is 13103011303. The next prime is 13103011319. The reversal of 13103011313 is 31311030131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13103011313 - 2³² = 8808044017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13103011291 and 13103011300.

It is not an unprimeable number, because it can be changed into a prime (13103011319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 935929373 + ... + 935929386.

It is an arithmetic number, because the mean of its divisors is an integer number (3743717520).

Almost surely, 2^13103011313 is an apocalyptic number.

It is an amenable number.

13103011313 is a deficient number, since it is larger than the sum of its proper divisors (1871858767).

13103011313 is an equidigital number, since it uses as much as digits as its factorization.

13103011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1871858766.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13103011313 its reverse (31311030131), we get a palindrome (44414041444).

The spelling of 13103011313 in words is "thirteen billion, one hundred three million, eleven thousand, three hundred thirteen".