13103020127 has 2 divisors, whose sum is σ = 13103020128. Its totient is φ = 13103020126.

The previous prime is 13103020093. The next prime is 13103020129. The reversal of 13103020127 is 72102030131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13103020127 - 2⁸ = 13103019871 is a prime.

It is a super-2 number, since 2×13103020127² (a number of 21 digits) contains 22 as substring.

Together with 13103020129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13103020099 and 13103020108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103020129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551510063 + 6551510064.

It is an arithmetic number, because the mean of its divisors is an integer number (6551510064).

Almost surely, 2^13103020127 is an apocalyptic number.

13103020127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103020127 is an equidigital number, since it uses as much as digits as its factorization.

13103020127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 13103020127 its reverse (72102030131), we get a palindrome (85205050258).

The spelling of 13103020127 in words is "thirteen billion, one hundred three million, twenty thousand, one hundred twenty-seven".