Base | Representation |
---|---|
bin | 11000011010000000… |
… | …01000011001101001 |
3 | 1020211011200101220200 |
4 | 30031000020121221 |
5 | 203313334240410 |
6 | 10004111342413 |
7 | 642464001051 |
oct | 141500103151 |
9 | 36734611820 |
10 | 13103040105 |
11 | 5614362a71 |
12 | 2658221a09 |
13 | 130a83b18c |
14 | 8c430c561 |
15 | 51a5073c0 |
hex | 30d008669 |
13103040105 has 24 divisors (see below), whose sum is σ = 24047933832. Its totient is φ = 6577211904.
The previous prime is 13103040079. The next prime is 13103040143. The reversal of 13103040105 is 50104030131.
It can be written as a sum of positive squares in 4 ways, for example, as 5571577449 + 7531462656 = 74643^2 + 86784^2 .
It is not a de Polignac number, because 13103040105 - 28 = 13103039849 is a prime.
It is a super-2 number, since 2×131030401052 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8563314 + ... + 8564843.
It is an arithmetic number, because the mean of its divisors is an integer number (1001997243).
Almost surely, 213103040105 is an apocalyptic number.
13103040105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13103040105 is a deficient number, since it is larger than the sum of its proper divisors (10944893727).
13103040105 is a wasteful number, since it uses less digits than its factorization.
13103040105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17128185 (or 17128182 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 18.
Adding to 13103040105 its reverse (50104030131), we get a palindrome (63207070236).
The spelling of 13103040105 in words is "thirteen billion, one hundred three million, forty thousand, one hundred five".
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