Base | Representation |
---|---|
bin | 11101110010110000001010… |
… | …000011101011000011111101 |
3 | 122011221102222211201220120211 |
4 | 131302300022003223003331 |
5 | 114133303022414020331 |
6 | 1142402454042312421 |
7 | 36412452045466252 |
oct | 3562601203530375 |
9 | 564842884656524 |
10 | 131031031001341 |
11 | 38828a48034779 |
12 | 128428371b8711 |
13 | 58162336b8983 |
14 | 244dd1594b429 |
15 | 10236401e08b1 |
hex | 772c0a0eb0fd |
131031031001341 has 2 divisors, whose sum is σ = 131031031001342. Its totient is φ = 131031031001340.
The previous prime is 131031031001323. The next prime is 131031031001369. The reversal of 131031031001341 is 143100130130131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76874825373241 + 54156205628100 = 8767829^2 + 7359090^2 .
It is a cyclic number.
It is not a de Polignac number, because 131031031001341 - 215 = 131031030968573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131031031001141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515515500670 + 65515515500671.
It is an arithmetic number, because the mean of its divisors is an integer number (65515515500671).
Almost surely, 2131031031001341 is an apocalyptic number.
It is an amenable number.
131031031001341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031031001341 is an equidigital number, since it uses as much as digits as its factorization.
131031031001341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 131031031001341 its reverse (143100130130131), we get a palindrome (274131161131472).
The spelling of 131031031001341 in words is "one hundred thirty-one trillion, thirty-one billion, thirty-one million, one thousand, three hundred forty-one".
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