Base | Representation |
---|---|
bin | 11000011010000000… |
… | …11010000101011101 |
3 | 1020211011211002021111 |
4 | 30031000122011131 |
5 | 203313344100131 |
6 | 10004113102021 |
7 | 642464422201 |
oct | 141500320535 |
9 | 36734732244 |
10 | 13103112541 |
11 | 5614402432 |
12 | 2658257911 |
13 | 130a86513c |
14 | 8c432ab01 |
15 | 51a51dab1 |
hex | 30d01a15d |
13103112541 has 2 divisors, whose sum is σ = 13103112542. Its totient is φ = 13103112540.
The previous prime is 13103112467. The next prime is 13103112553. The reversal of 13103112541 is 14521130131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8694816516 + 4408296025 = 93246^2 + 66395^2 .
It is a cyclic number.
It is not a de Polignac number, because 13103112541 - 27 = 13103112413 is a prime.
It is a super-2 number, since 2×131031125412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13103112571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551556270 + 6551556271.
It is an arithmetic number, because the mean of its divisors is an integer number (6551556271).
Almost surely, 213103112541 is an apocalyptic number.
It is an amenable number.
13103112541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103112541 is an equidigital number, since it uses as much as digits as its factorization.
13103112541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 13103112541 its reverse (14521130131), we get a palindrome (27624242672).
The spelling of 13103112541 in words is "thirteen billion, one hundred three million, one hundred twelve thousand, five hundred forty-one".
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