Base | Representation |
---|---|
bin | 11101110010110000010110… |
… | …001011010001011100001100 |
3 | 122011221110112000022120112201 |
4 | 131302300112023101130030 |
5 | 114133303431441221030 |
6 | 1142402530144211244 |
7 | 36412460064615400 |
oct | 3562602613213414 |
9 | 564843460276481 |
10 | 131031234320140 |
11 | 38829041884140 |
12 | 12842893309b24 |
13 | 581626686575b |
14 | 244dd34955100 |
15 | 1023652ea32ca |
hex | 772c162d170c |
131031234320140 has 144 divisors (see below), whose sum is σ = 349242033569184. Its totient is φ = 40834786944000.
The previous prime is 131031234320111. The next prime is 131031234320177. The reversal of 131031234320140 is 41023432130131.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a junction number, because it is equal to n+sod(n) for n = 131031234320099 and 131031234320108.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 71329824 + ... + 73143736.
It is an arithmetic number, because the mean of its divisors is an integer number (2425291899786).
Almost surely, 2131031234320140 is an apocalyptic number.
131031234320140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131031234320140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174621016784592).
131031234320140 is an abundant number, since it is smaller than the sum of its proper divisors (218210799249044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031234320140 is a wasteful number, since it uses less digits than its factorization.
131031234320140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1820648 (or 1820639 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 131031234320140 its reverse (41023432130131), we get a palindrome (172054666450271).
The spelling of 131031234320140 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred thirty-four million, three hundred twenty thousand, one hundred forty".
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