Base | Representation |
---|---|
bin | 11101110010110000011010… |
… | …111000101001010110001001 |
3 | 122011221110201111222100122102 |
4 | 131302300122320221112021 |
5 | 114133304112202322101 |
6 | 1142402542045403145 |
7 | 36412462044260531 |
oct | 3562603270512611 |
9 | 564843644870572 |
10 | 131031313323401 |
11 | 38829082434497 |
12 | 128428b58694b5 |
13 | 581627a03724a |
14 | 244dd4123c4c1 |
15 | 1023659dab86b |
hex | 772c1ae29589 |
131031313323401 has 4 divisors (see below), whose sum is σ = 131119077098052. Its totient is φ = 130943549548752.
The previous prime is 131031313323301. The next prime is 131031313323403. The reversal of 131031313323401 is 104323313130131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 123651642255376 + 7379671068025 = 11119876^2 + 2716555^2 .
It is a cyclic number.
It is not a de Polignac number, because 131031313323401 - 214 = 131031313307017 is a prime.
It is a super-2 number, since 2×1310313133234012 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (131031313323403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43881885086 + ... + 43881888071.
It is an arithmetic number, because the mean of its divisors is an integer number (32779769274513).
Almost surely, 2131031313323401 is an apocalyptic number.
It is an amenable number.
131031313323401 is a deficient number, since it is larger than the sum of its proper divisors (87763774651).
131031313323401 is an equidigital number, since it uses as much as digits as its factorization.
131031313323401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87763774650.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 131031313323401 its reverse (104323313130131), we get a palindrome (235354626453532).
The spelling of 131031313323401 in words is "one hundred thirty-one trillion, thirty-one billion, three hundred thirteen million, three hundred twenty-three thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •