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131032300111 is a prime number
BaseRepresentation
bin111101000001000100…
…0100011101001001111
3110112012212101112011021
41322002020203221033
54121323232100421
6140110112535011
712316050113446
oct1720210435117
9415185345137
10131032300111
1150630354519
122148a551467
13c482a108bb
1464b0623d5d
15361d7c5341
hex1e82223a4f

131032300111 has 2 divisors, whose sum is σ = 131032300112. Its totient is φ = 131032300110.

The previous prime is 131032300081. The next prime is 131032300123. The reversal of 131032300111 is 111003230131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131032300111 - 221 = 131030202959 is a prime.

It is a super-2 number, since 2×1310323001112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131032300141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516150055 + 65516150056.

It is an arithmetic number, because the mean of its divisors is an integer number (65516150056).

Almost surely, 2131032300111 is an apocalyptic number.

131032300111 is a deficient number, since it is larger than the sum of its proper divisors (1).

131032300111 is an equidigital number, since it uses as much as digits as its factorization.

131032300111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131032300111 its reverse (111003230131), we get a palindrome (242035530242).

The spelling of 131032300111 in words is "one hundred thirty-one billion, thirty-two million, three hundred thousand, one hundred eleven".