13103441543130 has 32 divisors (see below), whose sum is σ = 31533949810944. Its totient is φ = 3484729955136.

The previous prime is 13103441543053. The next prime is 13103441543149. The reversal of 13103441543130 is 3134514430131.

It is a junction number, because it is equal to n+sod(n) for n = 13103441543091 and 13103441543100.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 595058997 + ... + 595081016.

It is an arithmetic number, because the mean of its divisors is an integer number (985435931592).

Almost surely, 2^{13103441543130} is an apocalyptic number.

13103441543130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13103441543130 is an abundant number, since it is smaller than the sum of its proper divisors (18430508267814).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103441543130 is a wasteful number, since it uses less digits than its factorization.

13103441543130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1190140390.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 13103441543130 its reverse (3134514430131), we get a palindrome (16237955973261).

The spelling of 13103441543130 in words is "thirteen trillion, one hundred three billion, four hundred forty-one million, five hundred forty-three thousand, one hundred thirty".